Interactive explorer — grab vertex A, B or C and drag it. The angles and the sides are recalculated live.
α + β + γ = 180°
α′ = 180° − α = β + γ
α′ + β′ + γ′ = 360°
α, β, γ = interior angles at vertices A, B, C
α′, β′, γ′ = exterior angles (supplements to 180°)
a = BC, b = AC, c = AB (sides)
triangle inequality: a + b > c, a + c > b, b + c > a
A triangle is a plane figure with three vertices and three sides. No matter how we draw it, the sum of its interior angles is always exactly 180°. Thanks to that it is enough to know two angles and the third one is found by subtracting from 180°.
If one of the sides is extended beyond a vertex, an exterior angle appears. It is the supplement of the interior angle to 180° and, by the exterior angle theorem, it equals the sum of the two interior angles at the remaining vertices. The sum of all three exterior angles is 360°. For a triangle to be constructible at all, the triangle inequality must hold: the sum of any two sides is greater than the third side.
Drag vertices A, B, C exterior anglesre-center
✓ The sum of the interior angles is always exactly 180°
✓ The sum of the exterior angles is always 360° · α′ = β + γ
| Side | Length | Value |
|---|---|---|
| Side a (BC) | – | |
| Side b (AC) | – | |
| Side c (AB) | – |
Solve it step by step — the next step unlocks only after a correct answer. You can type decimals with a dot or a comma.